32x+124=-2x^2-2

Solution for 32x+124=-2x^2-2 equation:

32x+124=-2x^2-2

We move all terms to the left:

32x+124-(-2x^2-2)=0

We get rid of parentheses

2x^2+32x+2+124=0

We add all the numbers together, and all the variables

2x^2+32x+126=0

a = 2; b = 32; c = +126;
Δ = b2-4ac
Δ = 322-4·2·126
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4}{2*2}=\frac{-36}{4}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4}{2*2}=\frac{-28}{4}
=-7
$